# Algebra I/Solving Equations/Solving Equations with Variables on Both Sides of the Equation

Back to Table of Contents Algebra I

(Note to contributors: Please use the ^ symbol to designate exponents when you enter them in the wikibook. I will format them on the student-user interface.--HSTutorials 00:42, 17 July 2006 (UTC)

## Vocabulary

Variable - a letter (A-Z) that takes the place of a number.

Equation - an example would be: 8y - 3 = 1 + 10y (The answer is -2 [negative two] = y)

## Lesson

NOTE: WHAT YOU DO TO ONE SIDE YOU * MUST* DO TO THE OTHER! NO EXCEPTIONS!

1) do the distributive property.

2) Combine like terms on both sides.

3) add/subtract numbers next to a variable on both sides.

4) divide by the number next to the variable on both sides.

5) The answer should look like: *x*=20 or 20=*x*

(Note: the variables and numbers may vary in your answer.)

## Example Problems

A simple problem:

$10+50=3x-50+50$<---get rid of the 50 by subtracting

$60=3x$<---This is what your left with.

$60/3=3x/3$<---Get rid of the three by dividing by three

$20=x$<---This is your answer.

## Practice Games

Put links here to games that reinforce these skills

Purplemath.com: http://www.purplemath.com/modules/index.htm

## Practice Problems

(Note: put answer in parentheses after each problem you write)

Practice Problem #1:

3v - 2 = v + 16 {v = 9}

Practice Problem #2:

2x = 15 - x {x = 5}

Practice Problem #3:

([z - 5] / -3) = 9 + 3.4z {z = _?_}

Note: Help with Problems 2 & 3. No answer!